External form with Ajax to prevent page reload. Need Help

Im trying to create and external form that uses ajax to submit the form without reloading the page. I need an external form so that I can process the data and insert into a separate database, so i cant use the regular form block. Below are my code blocks for each page. I shortened the code to keep it simple. The form submits, but then in the main content section a whole new instance of my page appears. SO i have the main page, and withing the body, i get "thanks" for submission completion, but below it a whole new duplicate webpage within the content block. Can anyone help with this.

$form = Loader::helper('form');
defined('C5_EXECUTE') or die("Access Denied.");
<form  action="<?php echo $this->action('ajax_search')?>" method="post" id="ajax_search">
<div class="form2"><label for="fn">*First Name: </label> <?php echo $form->text('fn')?> &nbsp;
<label for="mn">M: </label> <input maxLength=50 size=2 name=mn id=mn class="font11"> &nbsp;
 <label for="ln">*Last Name: </label> <?php echo $form->text('ln')?></div>
<div class="form1"><label for="emai">*Email: </label> 
<?php echo $form->text('email')?> </div>
 <div class="form1"><input type="submit" name="submit" value="Submit" /></div>

defined('C5_EXECUTE') or die("Access Denied.");
class AjaxFormExternalFormBlockController extends BlockController {
      public function on_page_view() {
         $html = Loader::helper('html');
   public function action_ajax_search() {
   $form = Loader::helper('form');
   $txt = Loader::helper('text');
   $fname = $txt->sanitize($_POST['fn']);    
   $mname = $txt->sanitize($_POST['mn']);    
   $lname = $txt->sanitize($_POST['ln']);  
   $email = $txt->sanitize($_POST['email']);  
   $db = Loader::db();

      var action = $(this).attr('action');
      $.post(action, { 
         actio: $('#actio').val(),
         fn: $('#fn').val(),
         ln: $('#ln').val(),
         mn: $('#mn').val(),
         email: $('#email').val(),
            $('#ajax_search #submit').attr('disabled','');
            $('#ajax_search').before('<p class="response">'+data+'</p>');

View Replies:
wavemedia replied on at Permalink Reply
code is processing, but not correctly.